y^3/2=5y

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Solution for y^3/2=5y equation: 


y in (-oo:+oo)

(y^3)/2 = 5*y // - 5*y

(y^3)/2-(5*y) = 0

(y^3)/2-5*y = 0

1/2*y^3-5*y = 0

y*(1/2*y^2-5) = 0

1/2*y^2 = 5 // : 1/2

y^2 = 10

y^2 = 10 // ^ 1/2

abs(y) = 10^(1/2)

y = 10^(1/2) or y = -10^(1/2)

y = 0

y = 0

y in { 10^(1/2), -10^(1/2), 0 }

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